[백준 Java] 정렬: - 11651번: 좌표 정렬하기2

 

 

import java.io.*;
import java.util.Arrays;
import java.util.StringTokenizer;

public class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
        StringTokenizer st;
        StringBuilder sb = new StringBuilder();

        int N = Integer.parseInt(br.readLine());

        int[][] arr = new int[N][2];

        for(int i = 0; i < N; i++) {
            st = new StringTokenizer(br.readLine());
            arr[i][0] = Integer.parseInt(st.nextToken());
            arr[i][1] = Integer.parseInt(st.nextToken());
        }

        Arrays.sort(arr, (a1, a2) -> {
            if(a2[1] == a1[1]) {
                return a1[0] - a2[0]; // y좌표가 같다면 x좌표를 기준으로 오름차순 정렬
            } else {
                return a1[1] - a2[1]; // y좌표를 기준으로 오름차순 정렬
            }
        });

        for(int i = 0 ; i< N ; i++) {
            sb.append(arr[i][0] + " " + arr[i][1]).append('\n');
        }

        bw.write(String.valueOf(sb));

        br.close();
        bw.flush();
        bw.close();
    }
}